RUTGERS
Mathematics Department Sunday, Nov 22, 2009

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Wednesday 6/23

Numbers in parentheses indicate corresponding sections in the textbook.

Euler Phi Function (7.1)

We defined arithmetic function, multiplicative function, and completly multiplicative function. We proved that the Euler Phi function defined on Monday is multiplicative. This allowed us to prove the formula
φ(n)=n ∏ (1-1/pi)
where n=p1a1p2a2...pkak is the prime power factorization of n and the product runs over i=1...k.

We then defined the summatory function of an arithmetic function f(n) to be
F(n) = ∑ f(d) where the sum is taken over all divisors d of n.

An example led us to the remarkable identity
∑ φ(d) = n where the sum is taken over all divisors d of n.

We proved this identity by partitioning the integers from 1 to n into the classes Ck, such that j is in Ck if and only if (n,j)=k which is equivalent to (n/k,j/k)=1. This last condition shows that there are φ(n/k) integers in the class Ck thus proving the identity.

Sum and Number of Divisors (7.2)

We used the summatory functions of 1 and n to define the number of divisors function and the sum of divisors function as follows
The number of divisors of n is given by τ(n)=∑ 1 where the sum is taken over all divisors d of n
The sum of divisors of n is given by σ(n)=∑ d where the sum is taken over all divisors d of n

We proved that the summatory function of a multiplicative function is multiplicative, which immediately implied that τ(n) and σ(n) are multiplicative.

This allowed us to prove the following formulas for τ(n) and σ(n)
τ(n)= ∏ (ai+1)
σ(n)= ∏ (piai+1-1)/(pi-1)
where both products are for i=1..k and n=p1a1p2a2...pkak is the prime power factorization of n.

Perfect Numbers and Mersenne Primes (7.3)

A positive integer n is called perfect if σ(n)=2n.

We showed that n is an even perfect number if and only if it has the form
n=2m-1(2m-1)
where (2m-1) is prime and m>2

A prime is called a Mersenne prime if it has the form 2m-1, thus even perfect numbers are related to Mersenne primes.

We used the two nice lemmas proved at the end of Thursday June 10th's lecture to show that 2m-1, is prime only if m is prime. We pointed out that there is a fairly quick way to check wether a number of the form 2m-1 is a Mersenne Prime, which is called the Lucas-Lehmer test. We also noted that we conjecture that there are infinitely many Mersenne primes, but we have no proof. This is of course equivalent to the conjecture that there are infinitely many even perfect numbers.

Finally, nobody has ever seen an odd perfect number, but we can't prove that none exist.

You can learn a lot more about Mersenne primes here.


Saša Radomirović